To find three consecutive even integers that sum up to 30, we can start by defining the integers. Let’s represent the first even integer as x. The next two consecutive even integers can then be expressed as x + 2 and x + 4.
Now, we can set up an equation based on the information given:
x + (x + 2) + (x + 4) = 30
This simplifies to:
3x + 6 = 30
Next, we’ll isolate x by first subtracting 6 from both sides:
3x = 24
Now, divide both sides by 3:
x = 8
So, the first even integer is 8. The next two integers are:
- x + 2 = 10
- x + 4 = 12
Therefore, the three consecutive even integers are 8, 10, and 12.