What is the value of a in the equation a^2 + 3a + 8?

To solve the equation a2 + 3a + 8 = 0, we can use the quadratic formula, which is a = (-b ± √(b² – 4ac)) / 2a. Here, the coefficients are:

  • a (the coefficient of a2): 1
  • b (the coefficient of a): 3
  • c (the constant term): 8

Plugging in these values into the quadratic formula:

a = ( -3 ± √(3² – 4 * 1 * 8) ) / (2 * 1)

Calculating the discriminant:

3² = 9 and 4 * 1 * 8 = 32, so:

9 – 32 = -23

Since the discriminant is negative, this means the equation has no real solutions. Instead, it has two complex solutions.

Thus, the final answers can be expressed as:

a = (-3 ± √(-23)i) / 2

So the value of a can be expressed in terms of complex numbers.

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