Factorize the following: 3x² + 10x + 8

To factor the quadratic expression 3x² + 10x + 8, we need to find two binomials that multiply together to give us this expression.

We start with the standard form of a quadratic, ax² + bx + c, where:

  • a = 3
  • b = 10
  • c = 8

Next, we need to find two numbers that multiply to a * c = 3 * 8 = 24 and add up to b = 10.

The numbers that meet these criteria are 6 and 4 because:

  • 6 * 4 = 24
  • 6 + 4 = 10

Now we can rewrite the middle term (10x) using 6 and 4:

3x² + 6x + 4x + 8

Next, we group the terms to factor by grouping:

  • (3x² + 6x) + (4x + 8)

Factoring out common factors from each group gives us:

  • 3x(x + 2) + 4(x + 2)

Now, we can factor out the common binomial factor, which is (x + 2):

(x + 2)(3x + 4)

Thus, the factorization of 3x² + 10x + 8 is:

(x + 2)(3x + 4)

More Related Questions