To find the roots of the function f(x) = x² – 48, we need to solve the equation f(x) = 0.
This means we set the equation:
x² – 48 = 0
Next, we can isolate x²:
x² = 48
Now, to find x, we take the square root of both sides:
x = ±√48
Since √48 can be simplified, we can break it down further:
√48 = √(16 × 3) = √16 × √3 = 4√3
Thus, the roots can be expressed as:
x = 4√3 and x = -4√3
In conclusion, the roots of the function f(x) = x² – 48 are:
x = 4√3 and x = -4√3