To solve the system of linear equations x + 3y = 2 and x + 3y = 16, we can start by noting that both equations are actually expressing the same linear relationship between x and y.
If we look closely, we can see that both equations have the same left-hand side (LHS): x + 3y. However, they have different right-hand sides (RHS), where one equals 2 and the other equals 16. This suggests a contradiction.
Since both equations cannot be true simultaneously, there is no solution to this system. In fact, these lines are parallel to each other and thus do not intersect.
In summary, the conclusion is that there is no solution to this system of equations as they contradict each other.