To find the minimum volume of water needed to dissolve 1.00 g of benzoic acid at 100 degrees Celsius, we can use the solubility data provided. From the information, we know that the solubility of benzoic acid at this temperature is 6.80 g per 100 ml of water.
Using the proportion, we can set up the following equation:
6.80 g of benzoic acid dissolves in 100 ml of water.
Let V be the volume of water required to dissolve 1.00 g of benzoic acid:
1.00 g / 6.80 g = V / 100 ml
By cross-multiplying, we find:
V = (1.00 g * 100 ml) / 6.80 g
V = 14.71 ml
Therefore, the minimum volume of water needed to dissolve 1.00 g of benzoic acid at 100 degrees Celsius is approximately 14.71 ml.