What is the chance that a child of two heterozygous parents for freckles will have freckles?

To determine the chance that a child of two heterozygous parents (Ff) will have freckles, we can use a simple Punnett square to visualize the genetic combinations.

In this case, the alleles for freckles are as follows:

  • F: Freckles (dominant)
  • f: No freckles (recessive)

Since both parents are heterozygous (Ff), we set up the Punnett square like this:

F f
F FF Ff
f Ff ff

From the Punnett square, we can see the possible genetic combinations for their children:

  • FF: Homozygous dominant (freckles)
  • Ff: Heterozygous (freckles)
  • ff: Homozygous recessive (no freckles)

In terms of probabilities:

  • 25% chance of FF (freckles)
  • 50% chance of Ff (freckles)
  • 25% chance of ff (no freckles)

Overall, there is a total of 75% chance (25% + 50%) that the child will have freckles (either FF or Ff) and a 25% chance that the child will not have freckles (ff). Therefore, the chance that their child will have freckles is 75%.

More Related Questions