To determine the chance that a child of two heterozygous parents (Ff) will have freckles, we can use a simple Punnett square to visualize the genetic combinations.
In this case, the alleles for freckles are as follows:
- F: Freckles (dominant)
- f: No freckles (recessive)
Since both parents are heterozygous (Ff), we set up the Punnett square like this:
| F | f | |
|---|---|---|
| F | FF | Ff |
| f | Ff | ff |
From the Punnett square, we can see the possible genetic combinations for their children:
- FF: Homozygous dominant (freckles)
- Ff: Heterozygous (freckles)
- ff: Homozygous recessive (no freckles)
In terms of probabilities:
- 25% chance of FF (freckles)
- 50% chance of Ff (freckles)
- 25% chance of ff (no freckles)
Overall, there is a total of 75% chance (25% + 50%) that the child will have freckles (either FF or Ff) and a 25% chance that the child will not have freckles (ff). Therefore, the chance that their child will have freckles is 75%.