To find two numbers that add up to 4 and multiply to 6, let’s use two variables, x and y. We can set up the following equations based on the problem:
- x + y = 4
- x * y = 6
From the first equation, we can express y in terms of x:
y = 4 – x
Now we can substitute this expression for y into the second equation:
x * (4 – x) = 6
This simplifies to:
4x – x2 = 6
Rearranging gives us a quadratic equation:
x2 – 4x + 6 = 0
Next, we apply the quadratic formula:
x = (-b ± √(b2 – 4ac)) / (2a)
Here, a = 1, b = -4, and c = 6. Plugging in these values:
x = (4 ± √((-4)2 – 4 * 1 * 6)) / (2 * 1)
x = (4 ± √(16 – 24)) / 2
x = (4 ± √(-8)) / 2
Since the term inside the square root is negative, this means there are no real solutions for x and y under these conditions. Therefore, there are no two real numbers that both add up to 4 and multiply to 6.