To find the dimensions of the basketball court, we can set up a system of equations based on the information provided.
Let the width of the court be represented as w. According to the problem, the length is 42 ft longer than the width, so we can express the length as l = w + 42.
The formula for the perimeter (P) of a rectangle is given by:
P = 2(l + w)
Plugging in the given perimeter:
280 = 2((w + 42) + w)
Now, we simplify this equation:
280 = 2(2w + 42)
280 = 4w + 84
Next, we isolate w:
280 – 84 = 4w
196 = 4w
w = 49
Now that we have the width, we can find the length:
l = w + 42 = 49 + 42 = 91
Thus, the dimensions of the basketball court are:
- Width: 49 ft
- Length: 91 ft