How Much Heat is Required to Cool a Jogger by 2.66 Degrees Celsius?

To find out how much heat is needed to cool a jogger who weighs 76.8 kg by 2.66 degrees Celsius, we can use the specific heat capacity formula:

Q = mcΔT

Where:

  • Q = heat energy (in joules)
  • m = mass (in kg)
  • c = specific heat capacity (in J/kg·°C)
  • ΔT = change in temperature (°C)

Here, the mass m is 76.8 kg, the specific heat capacity c is 3500 J/kg·°C, and the change in temperature ΔT is 2.66 °C.

Now, we can plug in these values:

Q = 76.8 kg × 3500 J/kg·°C × 2.66 °C

Calculating this gives us:

Q = 76.8 × 3500 × 2.66 = 717,168 J

Therefore, the heat required to cool the jogger by 2.66 degrees Celsius is approximately 717,168 joules.

It’s important to note that this calculation assumes that the jogger’s body temperature and conditions remain constant, and it doesn’t account for factors like sweat evaporation or environmental conditions, which could also affect cooling.

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