Draw the structure of molecular formula C8H10O that produced the 1H NMR spectra shown below. The IR spectra does not show a broad absorbance at 3300 cm^-1 or a strong absorbance at 1710 cm^-1.

To determine the structure of a compound with the molecular formula C₈H₁₀O, we need to analyze the given spectral data. Since the IR spectrum does not exhibit a broad absorbance at 3300 cm^-1 (which would suggest the presence of an -OH group) or a strong absorbance at 1710 cm^-1 (indicative of a carbonyl group, such as -C=O), we can conclude that the compound does not contain alcohol or ketone/aldehyde functional groups.

The formula C₈H₁₀O suggests a degree of unsaturation, which could imply the presence of a ring or a double bond in the structure. Given the lack of typical functional groups found in the IR spectrum, this compound is likely an aromatic compound due to the high hydrogen content relative to carbon.

A plausible structure for C₈H₁₀O that fits these conditions is ethyl phenyl ether (or phenetole). This structure contains a phenyl group (C₆H₅) attached to an ethoxy (-OCH₂CH₃) group, providing a good balance of carbon and hydrogen while incorporating oxygen without introducing the characteristic IR signals of alcohols or aldehydes.

In summary, the molecular structure of C₈H₁₀O could be represented as follows: