What is the molar mass of Ca(CH3COO)2?

The molar mass of calcium acetate, represented as Ca(CH₃COO)₂, can be calculated by adding up the molar masses of all the individual atoms in the formula.

First, let’s break it down:

• Calcium (Ca) has a molar mass of approximately 40.08 g/mol.
• For the acetate ions (CH₃COO^–), each acetate molecule contains:
• 2 Carbon (C) atoms: 2 x 12.01 g/mol = 24.02 g/mol
• 3 Hydrogen (H) atoms: 3 x 1.008 g/mol = 3.024 g/mol
• 2 Oxygen (O) atoms: 2 x 16.00 g/mol = 32.00 g/mol
• So, the molar mass of one acetate ion is 24.02 + 3.024 + 16.00 = 43.044 g/mol.

Since there are two acetate ions in calcium acetate, we multiply this by 2:

2 x 43.044 g/mol = 86.088 g/mol

Now, we’ll add the molar mass of calcium:

40.08 g/mol (Ca) + 86.088 g/mol (from 2 CH₃COO) = 126.168 g/mol

Therefore, the molar mass of Ca(CH₃COO)₂ is approximately 126.17 g/mol.