HClO, or hypochlorous acid, is classified as a weak acid. This is because, in solution, it does not fully dissociate into its ions. Instead, it establishes an equilibrium where only a fraction of the HClO molecules release protons (H+).
To find the pH of a 0.07 M HClO solution, we first need to know the dissociation constant (Ka) for HClO, which is approximately 3.0 x 10-8. We set up the equilibrium expression for the dissociation of HClO:
HClO ⇌ H+ + ClO–
Applying the expression for Ka:
Ka = [H+][ClO–] / [HClO]
Assuming that the initial concentration of HClO is 0.07 M and that ‘x’ is the change in concentration (the amount that dissociates), we can write:
Ka = (x)(x) / (0.07 – x) ≈ (x2) / 0.07, since x is small compared to 0.07.
Substituting the Ka value:
3.0 x 10-8 = x2 / 0.07
Solving for x:
x2 = 3.0 x 10-8 * 0.07 = 2.1 x 10-9
x ≈ 4.58 x 10-5 M (this is the concentration of H+ ions).
Next, we can find the pH:
pH = -log[H+] = -log(4.58 x 10-5) ≈ 4.34.
Therefore, rounding off, the pH of the 0.07 M HClO solution is approximately 4.3.
So the correct answer is c) 4.3.