The Lewis structure for sodium bromide (NaBr) can be drawn by considering the valence electrons of the involved atoms. Sodium (Na) has one valence electron, while bromine (Br) has seven valence electrons.
In the formation of NaBr, sodium donates its one valence electron to bromine, allowing bromine to complete its octet. Thus, sodium becomes a positively charged ion (Na+), and bromine becomes a negatively charged ion (Br–).
The Lewis structure illustrates this transfer of electrons. The sodium atom is represented as Na, while bromine is represented as Br with three pairs of dots around it, indicating its completed octet after gaining an electron. Because sodium loses one electron, it will not have any dots around it.
The final representation is simple: the symbol Na (indicating the sodium cation) and Br (indicating the bromide anion) are noted, with brackets used to show their charges:
[Na+] [Br–]
So, the Lewis structure for sodium bromide showcases the transfer and completion of their outer electron shells, and the compound is named sodium bromide.