There are four alkyl bromides with the formula C4H9Br. Write their structural formulas and classify each as primary, secondary, or tertiary alkyl bromides.

In organic chemistry, alkyl bromides are compounds that contain a bromine atom attached to an alkyl group. For the formula C4H9Br, we can derive four different structural formulas, classified as primary, secondary, or tertiary alkyl bromides. Here are the structures:

1. 1-Bromobutane (Primary alkyl bromide)

1-Bromobutane

In this structure, the bromine atom is attached to the end carbon of the butane chain, making it a primary alkyl bromide.

2. 2-Bromobutane (Secondary alkyl bromide)

2-Bromobutane

Here, the bromine atom is bonded to the second carbon in the chain, classifying it as a secondary alkyl bromide because the carbon bearing the bromine is attached to two other carbons.

3. 1-Bromo-2-methylpropane (Primary alkyl bromide)

1-Bromo-2-methylpropane

This compound also has the bromine attached to a terminal carbon (equivalent to 1-bromobutane) and is thus classified as a primary alkyl bromide.

4. 2-Bromo-2-methylpropane (Tertiary alkyl bromide)

2-Bromo-2-methylpropane

In this case, the bromine atom is connected to a carbon that is attached to three other carbons, making this a tertiary alkyl bromide.

In summary:

  • 1-Bromobutane: Primary
  • 2-Bromobutane: Secondary
  • 1-Bromo-2-methylpropane: Primary
  • 2-Bromo-2-methylpropane: Tertiary

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