To draw the Lewis structure for ASO33-, we begin by determining the total number of valence electrons available.
1. **Count the Valence Electrons**:
- Arsenic (As) has 5 valence electrons.
- Oxygen (O) has 6 valence electrons and there are three oxygen atoms, contributing a total of 18 valence electrons (3 × 6).
- Since the molecule has a 3- charge, we add 3 more electrons.
This gives us a total of: 5 (As) + 18 (3 O) + 3 (charge) = 26 valence electrons.
2. **Sketch the Skeleton Structure**:
Place arsenic (As) at the center and connect it to the three oxygen atoms with single bonds.
3. **Distribute Remaining Electrons**:
Initially, we used 6 electrons for the three As-O bonds, leaving us with 20 electrons to place. We start by fulfilling the octet rule for the oxygen atoms, adding 6 electrons (3 lone pairs) to each of the three O atoms. This utilizes 18 electrons, leaving us with 2 electrons.
4. **Form Double Bonds**:
Since arsenic can expand its octet, we can use the remaining 2 electrons to form a double bond between arsenic and one of the oxygen atoms. This ensures that one oxygen atom shares a total of 4 electrons with arsenic, achieving a stable octet for both atoms.
5. **Add Formal Charges**:
After arranging the electrons, check the formal charges. Oxygen with a double bond will have a formal charge of 0, while the other two oxygens with 3 lone pairs will have formal charges of -1 (for each). The arsenic will also have a formal charge of +1, which is acceptable for the molecule’s overall charge of -3.
6. **Final Structure**:
The final Lewis structure of ASO33- looks like this:
O O O || .. .. As - O - O
In conclusion, the Lewis structure for ASO33- exhibits double and single bonds that cater to the valence requirements and charge of the molecule.