What is the electron configuration for the Sr²⁺ ion?

The electron configuration for the strontium ion (Sr²⁺) is [Kr] or 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶. To understand how we arrive at this, let’s break it down:

Strontium (Sr) is located in group 2 of the periodic table and has an atomic number of 38. This means a neutral Sr atom has 38 electrons. The electron configuration of a neutral strontium atom is:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s²

This accounts for all 38 electrons. However, when strontium forms a Sr²⁺ ion, it loses two electrons. Typically, these electrons are removed from the outermost shell, which is the 5s orbital in this case. Therefore:

  • Start with the neutral Sr electron configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s²
  • Remove two electrons from the 5s orbital (which is actually the 4s for Sr): 1s² 2s² 2p⁶ 3s² 3p⁶
    (now we’re only left with 36 electrons).

This results in an electron configuration of [Kr], indicating that the Sr²⁺ ion has the same electron configuration as the noble gas krypton. This stable electron configuration is the reason strontium commonly forms a +2 ion.

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