NaBr, or sodium bromide, contains ionic bonds. This type of bond forms between sodium (Na) and bromine (Br) when sodium donates an electron to bromine, leading to the formation of charged ions. Sodium becomes a positively charged ion (Na+), and bromine becomes a negatively charged ion (Br–).
The strong electrostatic attraction between these oppositely charged ions results in the formation of an ionic bond. This characteristic is typical of compounds formed between metals and non-metals, where the metal tends to lose electrons and the non-metal tends to gain them.
In summary, the bond present in NaBr is ionic, which is a common type of bonding seen in many compounds formed from elements found in group 1 (alkali metals) and group 17 (halogens) of the periodic table.