To determine the minimum runway length required for the Cessna 150 to take off, we can use the kinematic equation that relates acceleration, initial velocity, final velocity, and distance:
d = (vf² – vi²) / (2a)
Where:
- d = distance (runway length in meters)
- vf = final velocity (takeoff speed)
- vi = initial velocity (0 m/s for takeoff)
- a = acceleration
In this case:
- vf = 34.8 m/s
- vi = 0 m/s
- a = 2.29 m/s²
Plugging in the values:
d = (34.8² – 0²) / (2 * 2.29)
Calculating this gives:
d = (1218.24) / 4.58
d ≈ 265.5 m
This means that the minimum runway length required for the Cessna 150 to take off at the specified conditions is approximately 265.5 meters.