What is the bond order of N2?

The bond order of N2 (nitrogen gas) is 3.

To understand this, we need to look at the molecular orbital configuration of nitrogen. The nitrogen atom has 7 electrons, so a diatomic nitrogen molecule (N2) consists of a total of 14 electrons. The molecular orbital diagram for N2 shows the filling of these electrons in the order of increasing energy levels:

  • σ(1s)2
  • σ*(1s)2
  • σ(2s)2
  • σ*(2s)2
  • σ(2p)2
  • π(2p)2
  • π*(2p)0
  • σ*(2p)0

So, we can count the number of bonding and antibonding electrons:

  • Bonding electrons = 10 (from σ(1s), σ(2s), σ(2p), and π(2p))
  • Antibonding electrons = 4 (from σ*(1s) and σ*(2s))

Bond order is given by the formula:

Bond Order = (Number of bonding electrons – Number of antibonding electrons) / 2

This yields:

Bond Order = (10 – 4) / 2 = 3

Therefore, the bond order of N2 is 3, indicating that there are three bonds between the two nitrogen atoms, which contributes to the stability and strength of the N2 molecule.

More Related Questions